It was found that the refractive index of the material of a certain prism varied as $\mu = 1.5 + 0.004 / \lambda^{2}$,where $\lambda$ is the wavelength of light used to measure the refractive index. The same material was then used to construct a thin prism of apex angle $10^{\circ}$. Angles of minimum deviation $\delta_{m}$ of the prism were recorded for the sources with wavelengths $\lambda_{1}$ and $\lambda_{2}$,respectively. Then,

• A
  $\delta_{m}(\lambda_{1}) < \delta_{m}(\lambda_{2})$ if $\lambda_{1} < \lambda_{2}$
• B
  $\delta_{m}(\lambda_{1}) > \delta_{m}(\lambda_{2})$ if $\lambda_{1} > \lambda_{2}$
• C
  $\delta_{m}(\lambda_{1}) > \delta_{m}(\lambda_{2})$ if $\lambda_{1} < \lambda_{2}$
• D
  $\delta_{m}$ is the same in both cases