Jairam purchased a house for Rs. 15000 and pa | vedclass

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(C) The total cost of the house is Rs. $15000$. Jairam paid Rs. $5000$ upfront,so the remaining balance is $15000 - 5000 = 10000$. He pays the remaini

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$20500$

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(C) The total cost of the house is Rs. $15000$. Jairam paid Rs. $5000$ upfront,so the remaining balance is $15000 - 5000 = 10000$. He pays the remaining Rs. $10000$ in $10$ annual installments of Rs. $1000$ each,plus $10\%$ interest on the outstanding balance. In the $1^{st}$ year,he pays: $1000 + (10\% 	ext{ of } 10000) = 1000 + 1000 = 2000$. In the $2^{nd}$ year,the outstanding balance is $9000$,so he pays: $1000 + (10\% 	ext{ of } 9000) = 1000 + 900 = 1900$. In the $3^{rd}$ year,the outstanding balance is $8000$,so he pays: $1000 + (10\% 	ext{ of } 8000) = 1000 + 800 = 1800$. This forms an Arithmetic Progression $(AP)$ where the first term $a = 2000$,common difference $d = -100$,and number of terms $n = 10$. The sum of these $10$ installments is $S_n = \frac{n}{2}[2a + (n-1)d]$. $S_{10} = \frac{10}{2}[2(2000) + (10-1)(-100)] = 5[4000 - 900] = 5[3100] = 15500$. The total amount paid by Jairam is the initial payment plus the sum of installments: $5000 + 15500 = 20500$.

Jairam purchased a house for Rs. $15000$ and paid Rs. $5000$ at once. He promised to pay the remaining amount in annual installments of Rs. $1000$ with $10\%$ per annum interest on the outstanding balance. What is the total amount paid by Jairam in Rs.?

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