Jairam purchased a house for Rs. 15000 and pa | vedclass

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(C) The total cost of the house is Rs. $15000$. Jairam paid Rs. $5000$ initially,so the remaining balance is $15000 - 5000 = 10000$. He pays this bala

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$20500$

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(C) The total cost of the house is Rs. $15000$. Jairam paid Rs. $5000$ initially,so the remaining balance is $15000 - 5000 = 10000$. He pays this balance in $10$ annual installments of Rs. $1000$ each,plus $10\%$ interest on the remaining balance. In the $1^{st}$ year,he pays $1000 + 10\% 	ext{ of } 10000 = 1000 + 1000 = 2000$. In the $2^{nd}$ year,he pays $1000 + 10\% 	ext{ of } 9000 = 1000 + 900 = 1900$. In the $3^{rd}$ year,he pays $1000 + 10\% 	ext{ of } 8000 = 1000 + 800 = 1800$. This forms an arithmetic progression with $a = 2000$,$d = -100$,and $n = 10$. The sum of the $10$ installments is $S_{10} = \frac{10}{2} [2(2000) + (10 - 1)(-100)] = 5 [4000 - 900] = 5 	imes 3100 = 15500$. The total money paid by Jairam is $5000 + 15500 = 20500$.

Jairam purchased a house for Rs. $15000$ and paid Rs. $5000$ at once. He promised to pay the remaining amount in annual installments of Rs. $1000$ with $10\%$ per annum interest on the outstanding balance. How much total money will be paid by Jairam in Rs.?

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