January 1, 2006 was a Sunday. What was the da | vedclass

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(A) The number of years between January $1, 2006$ and January $1, 2012$ is $2012 - 2006 = 6$ years.In these $6$ years,the leap years are $2008$ and $2

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Sunday

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(A) The number of years between January $1, 2006$ and January $1, 2012$ is $2012 - 2006 = 6$ years.In these $6$ years,the leap years are $2008$ and $2012$. However,since we are calculating up to January $1, 2012$,the leap day ($29$th February) of $2012$ has not yet occurred. Thus,only $2008$ is counted as a leap year.Number of leap years = $1$ $(2008)$.Number of ordinary years = $6 - 1 = 5$.Total odd days = $(1 	imes 2) + (5 	imes 1) = 2 + 5 = 7$ odd days.Since $7$ days correspond to $0$ odd days $(7 \pmod 7 = 0)$,the day of the week remains the same.Therefore,January $1, 2012$ was a Sunday.

January $1, 2006$ was a Sunday. What was the day of the week on January $1, 2012$?

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