The lanthanide for which +II and +III oxidati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The general oxidation state of lanthanoids is $+III$. However,some elements exhibit $+II$ or $+IV$ oxidation states due to stable electronic confi

Vedclass · Accepted Answer

$Eu$

Vedclass · Answer

(D) The general oxidation state of lanthanoids is $+III$. However,some elements exhibit $+II$ or $+IV$ oxidation states due to stable electronic configurations (like half-filled or fully-filled $f$-orbitals). Europium ($Eu$,atomic number $63$) has the electronic configuration $[Xe] 4f^7 6s^2$. It easily loses two electrons from the $6s$ orbital to form the $Eu^{2+}$ ion,which has a stable half-filled $4f^7$ configuration. It also commonly exists in the $+III$ oxidation state $(Eu^{3+})$. Therefore,$+II$ and $+III$ oxidation states are common for $Eu$.

The lanthanide for which $+II$ and $+III$ oxidation states are common is:

Similar Questions

Which element from the following has a half-filled $f$ orbital in the $+3$ oxidation state?

What is the highest oxidation state exhibited by actinoids?

Identify the rare earth element from the following.

The electronic configuration of Einsteinium is : (Given atomic number of Einsteinium $= 99$)

If the electronic configuration of $M^{3+}$ is $[Xe] \ 4f^3$,then $M^{3+}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module