Length,breadth,and thickness of a strip havin | vedclass

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(B) Given dimensions are: $L = 10.5 \ cm$ ($3$ significant figures),$b = 0.05 \ mm = 0.005 \ cm$ ($1$ significant figure),and $t = 6.0 \ \mu m = 6.0 \

Vedclass · Accepted Answer

$3 	imes 10^{-5}$

Vedclass · Answer

(B) Given dimensions are: $L = 10.5 \ cm$ ($3$ significant figures),$b = 0.05 \ mm = 0.005 \ cm$ ($1$ significant figure),and $t = 6.0 \ \mu m = 6.0 	imes 10^{-4} \ cm$ ($2$ significant figures). According to the rules of significant figures,the result of multiplication should have the same number of significant figures as the measurement with the least number of significant figures. Here,the least number of significant figures is $1$ (from $b = 0.05 \ mm$). Volume $V = L 	imes b 	imes t = 10.5 \ cm 	imes 0.005 \ cm 	imes 6.0 	imes 10^{-4} \ cm$. $V = 10.5 	imes 5 	imes 10^{-3} 	imes 6.0 	imes 10^{-4} \ cm^3 = 315 	imes 10^{-7} \ cm^3 = 3.15 	imes 10^{-5} \ cm^3$. Rounding to $1$ significant figure,we get $V = 3 	imes 10^{-5} \ cm^3$.

Length,breadth,and thickness of a strip having a uniform cross-section are measured to be $10.5 \ cm$,$0.05 \ mm$,and $6.0 \ \mu m$,respectively. Which of the following option$(s)$ give$(s)$ the volume of the strip in $cm^3$ with correct significant figures?

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