Length of a rectangle is twice of its breadth | vedclass

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(B) Let the breadth of the rectangle be $b$ meters.Given that the length is twice the breadth,so length $l = 2b$.The area of a rectangle is given by t

Vedclass · Accepted Answer

$18$

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(B) Let the breadth of the rectangle be $b$ meters.Given that the length is twice the breadth,so length $l = 2b$.The area of a rectangle is given by the formula $Area = l 	imes b$.Substituting the given values: $18 = (2b) 	imes b$.$18 = 2b^{2}$.$b^{2} = 9$.$b = 3 \, m$ (since breadth cannot be negative).Therefore,length $l = 2 	imes 3 = 6 \, m$.The perimeter of a rectangle is given by $P = 2(l + b)$.$P = 2(6 + 3) = 2(9) = 18 \, m$.

Length of a rectangle is twice of its breadth. Area of the rectangle is $18 \, m^{2}$. What would be its perimeter? (in $m$)

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