Let $f(x) = (\sin(\tan^{-1} x) + \sin(\cot^{-1} x))^2 - 1$ for $|x| > 1$. If $\frac{dy}{dx} = \frac{1}{2} \frac{d}{dx}(\sin^{-1}(f(x)))$ and $y(\sqrt{3}) = \frac{\pi}{6}$,then $y(-\sqrt{3})$ is equal to

  • A
    $\frac{5\pi}{6}$
  • B
    $-\frac{\pi}{6}$
  • C
    $\frac{\pi}{3}$
  • D
    $\frac{2\pi}{3}$

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