Let A = begin{bmatrix} 2 & 4 3 & 2 end{bmatr | vedclass

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(A) Given $A = \begin{bmatrix} 2 & 4 \ 3 & 2 \end{bmatrix}$ and $C = \begin{bmatrix} -2 & 5 \ 3 & 4 \end{bmatrix}$.First,calculate $3A$:$3A = 3 \beg

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$\begin{bmatrix} 8 & 7 \ 6 & 2 \end{bmatrix}$

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(A) Given $A = \begin{bmatrix} 2 & 4 \ 3 & 2 \end{bmatrix}$ and $C = \begin{bmatrix} -2 & 5 \ 3 & 4 \end{bmatrix}$.First,calculate $3A$:$3A = 3 \begin{bmatrix} 2 & 4 \ 3 & 2 \end{bmatrix} = \begin{bmatrix} 3 	imes 2 & 3 	imes 4 \ 3 	imes 3 & 3 	imes 2 \end{bmatrix} = \begin{bmatrix} 6 & 12 \ 9 & 6 \end{bmatrix}$.Now,subtract $C$ from $3A$:$3A - C = \begin{bmatrix} 6 & 12 \ 9 & 6 \end{bmatrix} - \begin{bmatrix} -2 & 5 \ 3 & 4 \end{bmatrix}$.Perform element-wise subtraction:$3A - C = \begin{bmatrix} 6 - (-2) & 12 - 5 \ 9 - 3 & 6 - 4 \end{bmatrix} = \begin{bmatrix} 6 + 2 & 7 \ 6 & 2 \end{bmatrix} = \begin{bmatrix} 8 & 7 \ 6 & 2 \end{bmatrix}$.

Let $A = \begin{bmatrix} 2 & 4 \\ 3 & 2 \end{bmatrix}$,$B = \begin{bmatrix} 1 & 3 \\ -2 & 5 \end{bmatrix}$,and $C = \begin{bmatrix} -2 & 5 \\ 3 & 4 \end{bmatrix}$. Find $3A - C$.

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