Let $A = \{1, 2, 3, 4, 5, 6\}$. Define a relation $R$ from $A$ to $A$ by $R = \{(x, y) : y = x + 1\}$. Depict this relation using an arrow diagram.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) By the definition of the relation,we have $R = \{(1, 2), (2, 3), (3, 4), (4, 5), (5, 6)\}$.
The corresponding arrow diagram is shown below:
Two sets $A$ are represented as ovals. The elements $\{1, 2, 3, 4, 5, 6\}$ are marked in both. Arrows are drawn from $x$ in the first set to $y$ in the second set such that $y = x + 1$. Specifically,arrows connect $1 \to 2$,$2 \to 3$,$3 \to 4$,$4 \to 5$,and $5 \to 6$.

Explore More

Similar Questions

If $A = \{(a, b) : 4a = 5b; a, b \in \{1, 2, 3, \dots, 30\}\}$,then the number of such ordered pairs $(a, b)$ is

If $R = \{(a, b) : b = a - 1, a \in \mathbb{Z}, 5 < a < 9\}$,then the range of $R$ is

If $R$ is a relation from a finite set $A$ having $m$ elements to a finite set $B$ having $n$ elements,then the number of relations from $A$ to $B$ is:

Let $R$ be a relation from $N$ to $N$ defined by $R = \{(a, b) : a, b \in N \text{ and } a = b^2\}$. Is the following statement true?
$(a, b) \in R$ implies $(b, a) \in R$

The figure shows a relation between the sets $P$ and $Q$. Write this relation in set-builder form. What are its domain and range?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo