Let $f(x) = x^{2}$ and $g(x) = 2x + 1$ be two real functions. Find $(f+g)(x)$,$(f-g)(x)$,$(fg)(x)$,and $(\frac{f}{g})(x)$.
- A$(f+g)(x) = x^{2}+2x+1, (f-g)(x) = x^{2}-2x-1, (fg)(x) = 2x^{3}+x^{2}, (\frac{f}{g})(x) = \frac{x^{2}}{2x+1}, x \neq -\frac{1}{2}$
- B$(f+g)(x) = x^{2}+2x+1, (f-g)(x) = x^{2}-2x+1, (fg)(x) = 2x^{3}+x^{2}, (\frac{f}{g})(x) = \frac{x^{2}}{2x+1}, x \neq -\frac{1}{2}$
- C$(f+g)(x) = x^{2}+2x-1, (f-g)(x) = x^{2}-2x-1, (fg)(x) = 2x^{3}-x^{2}, (\frac{f}{g})(x) = \frac{x^{2}}{2x+1}, x \neq -\frac{1}{2}$
- D$(f+g)(x) = x^{2}-2x+1, (f-g)(x) = x^{2}+2x+1, (fg)(x) = 2x^{3}+x^{2}, (\frac{f}{g})(x) = \frac{x^{2}}{2x+1}, x \neq -\frac{1}{2}$
Explore More
Similar Questions
If $f(a) = \log \left| \frac{1-a}{1+a} \right|$ for $a \neq \{-1, 1\}$,then the set of values of all $a$,for which $f\left( \frac{2a}{1+a^2} \right) > 0$ is
Which of the following statements is false?
DifficultAP EAMCET 2021
View SolutionGiven $f'(x) > 0$ and $g'(x) < 0$ for all $x \in R$,then which of the following is true?
The graph of the function $f(x) = x + \frac{1}{8} \sin(2 \pi x)$,$0 \leq x \leq 1$ is shown below. Define $f_1(x) = f(x)$,$f_{n+1}(x) = f(f_n(x))$,for $n \geq 1$.
Which of the following statements are true?
$I.$ There are infinitely many $x \in [0, 1]$ for which $\lim_{n \rightarrow \infty} f_n(x) = 0$
$II.$ There are infinitely many $x \in [0, 1]$ for which $\lim_{n \rightarrow \infty} f_n(x) = \frac{1}{2}$
$III.$ There are infinitely many $x \in [0, 1]$ for which $\lim_{n \rightarrow \infty} f_n(x) = 1$
$IV.$ There are infinitely many $x \in [0, 1]$ for which $\lim_{n \rightarrow \infty} f_n(x)$ does not exist.
Which of the following statements are true?
$I.$ There are infinitely many $x \in [0, 1]$ for which $\lim_{n \rightarrow \infty} f_n(x) = 0$
$II.$ There are infinitely many $x \in [0, 1]$ for which $\lim_{n \rightarrow \infty} f_n(x) = \frac{1}{2}$
$III.$ There are infinitely many $x \in [0, 1]$ for which $\lim_{n \rightarrow \infty} f_n(x) = 1$
$IV.$ There are infinitely many $x \in [0, 1]$ for which $\lim_{n \rightarrow \infty} f_n(x)$ does not exist.
$[t]$ denotes the greatest integer function and $[t-m] = [t] - m$ when $m \in \mathbb{Z}$. If $k = 2[2x - 1] - 1$ and $3[2x - 2] + 1 = 2[2x - 1] - 1$,then the range of $f(x) = [k + 5x]$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo