Let $\Delta, \nabla \in \{\wedge, \vee\}$ be such that $(p \nabla q) \Rightarrow ((p \nabla q) \nabla r)$ is a tautology. Then $(p \nabla q) \Delta r$ is logically equivalent to

  • A
    $(p \Delta r) \vee q$
  • B
    $(p \Delta r) \wedge q$
  • C
    $(p \wedge r) \Delta q$
  • D
    $(p \nabla r) \wedge q$

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