Let $A = \{n \in N : H.C.F.(n, 45) = 1\}$ and $B = \{2k : k \in \{1, 2, \ldots, 100\}\}$. Then the sum of all the elements of $A \cap B$ is

  • A
    $5264$
  • B
    $5265$
  • C
    $5255$
  • D
    $5235$

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