Let $[t]$ denote the greatest integer less than or equal to $t.$ Then,the value of the integral $\int\limits_{0}^{1}\left[-8 x^{2}+6 x-1\right] d x$ is equal to

  • A
    $-1$
  • B
    $-\frac{5}{4}$
  • C
    $\frac{\sqrt{17}-13}{8}$
  • D
    $\frac{\sqrt{17}-16}{8}$

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