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(C) The relation $R$ is defined on the set of natural numbers $N$ by the equation $x + 2y = 8$.We need to find pairs $(x, y)$ such that $x, y \in N$ a

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$\{2, 4, 6\}$

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(C) The relation $R$ is defined on the set of natural numbers $N$ by the equation $x + 2y = 8$.We need to find pairs $(x, y)$ such that $x, y \in N$ and $x + 2y = 8$.If $y = 1$,then $x + 2(1) = 8 \implies x = 6$.If $y = 2$,then $x + 2(2) = 8 \implies x = 4$.If $y = 3$,then $x + 2(3) = 8 \implies x = 2$.If $y = 4$,then $x + 2(4) = 8 \implies x = 0$. Since $0 
otin N$,this is not a valid pair.For any $y > 3$,$x$ will be negative,which is not in $N$.Thus,the relation $R = \{(2, 3), (4, 2), (6, 1)\}$.The domain of $R$ is the set of all first elements of the ordered pairs in $R$.Therefore,the domain is $\{2, 4, 6\}$.

Let $R$ be a relation on $N$ defined by $x + 2y = 8$. The domain of $R$ is

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