Let $f(x) = \frac{1-\tan x}{4x-\pi}$ for $x \neq \frac{\pi}{4}$ and $x \in [0, \frac{1}{2}]$. If $f(x)$ is continuous in $[0, \frac{\pi}{2}]$,then $f(\frac{\pi}{4})$ is

  • A
    $-\frac{1}{2}$
  • B
    $\frac{1}{2}$
  • C
    $1$
  • D
    $-1$

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