Let $a: \sim(p \wedge \sim r) \vee(\sim q \vee s)$ and $b: (p \vee s) \leftrightarrow(q \wedge r)$. If the truth values of $p$ and $q$ are $T$ and that of $r$ and $s$ are $F$,then the truth values of $a$ and $b$ are respectively...
- A$F, F$
- B$T, T$
- C$T, F$
- D$F, T$
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If $p$: Every square is a rectangle and $q$: Every rhombus is a kite,then the truth values of $p \rightarrow q$ and $p \leftrightarrow q$ are $ . . . . . . $ and $ . . . . . . $ respectively.
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View SolutionConsider the following statements:
Statement $I$: If a quadrilateral $ABCD$ is a square,then all of its sides are equal.
Statement $II$: If all the sides of a quadrilateral $ABCD$ are equal,then $ABCD$ is a square.
Then:
Statement $I$: If a quadrilateral $ABCD$ is a square,then all of its sides are equal.
Statement $II$: If all the sides of a quadrilateral $ABCD$ are equal,then $ABCD$ is a square.
Then:
Statement $-1 :$ $\sim (p \leftrightarrow \sim q)$ is equivalent to $p \leftrightarrow q$.
Statement $-2 :$ $\sim (p \leftrightarrow \sim q)$ is a tautology.
Statement $-2 :$ $\sim (p \leftrightarrow \sim q)$ is a tautology.
DifficultAIEEE 2009
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