Let theta be an angle in the standard positio | vedclass

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Question

(C) The point $(-5, 12)$ has a negative $x$-coordinate and a positive $y$-coordinate,which means it lies in the second quadrant. In the second quadran

Vedclass · Accepted Answer

$|	an 	heta| = -	an 	heta$

Vedclass · Answer

(C) The point $(-5, 12)$ has a negative $x$-coordinate and a positive $y$-coordinate,which means it lies in the second quadrant. In the second quadrant,$\sin 	heta$ and $\operatorname{cosec} 	heta$ are positive,while $\cos 	heta, \sec 	heta, 	an 	heta,$ and $\cot 	heta$ are negative. By the definition of the modulus function,for any value $x$,$|x| = x$ if $x \ge 0$ and $|x| = -x$ if $x Since $\sin 	heta > 0$,$|\sin 	heta| = \sin 	heta$. Since $\cos 	heta Since $	an 	heta Since $\operatorname{cosec} 	heta > 0$,$|\operatorname{cosec} 	heta| = \operatorname{cosec} 	heta$. Comparing these with the given options,option $C$ is correct.

Let $\theta$ be an angle in the standard position such that the point $(-5, 12)$ lies on its terminal side. Then:

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