Let $a, b$ and $c$ be the lengths of the sides of a triangle with its opposite angles $A, B$ and $C$ respectively. If $\angle C=60^{\circ}$,then the value of $\frac{c(a+b)+(a^2+b^2)}{(b+c)(c+a)}$ is

  • A
    $\frac{1}{2}$
  • B
    $\frac{\sqrt{3}}{2}$
  • C
    $1$
  • D
    $\sqrt{3}$

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