Let O be the origin and P be a point which is | vedclass

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(A) Given that the direction ratios of $\vec{OP}$ are $(a, b, c) = (1, -2, -2)$.First,we calculate the magnitude of the direction ratios vector: $\sqr

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$(1, -2, -2)$

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(A) Given that the direction ratios of $\vec{OP}$ are $(a, b, c) = (1, -2, -2)$.First,we calculate the magnitude of the direction ratios vector: $\sqrt{1^2 + (-2)^2 + (-2)^2} = \sqrt{1 + 4 + 4} = \sqrt{9} = 3$.The direction cosines $(l, m, n)$ are obtained by dividing the direction ratios by their magnitude:$l = \frac{1}{3}, m = \frac{-2}{3}, n = \frac{-2}{3}$.The coordinates of point $P$ at a distance $r = 3$ from the origin are given by $(lr, mr, nr)$.$P = (\frac{1}{3} 	imes 3, \frac{-2}{3} 	imes 3, \frac{-2}{3} 	imes 3) = (1, -2, -2)$.

Let $O$ be the origin and $P$ be a point which is at a distance of $3$ units from the origin. If the direction ratios of $\vec{OP}$ are $(1, -2, -2)$,then the coordinates of $P$ are

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