Let $\triangle ACB$ be a triangle with a right angle at $C$. Let $AB = 29$ units,$BC = 21$ units,and $\angle ABC = \theta$. Then $\cos^2 \theta - \sin^2 \theta = $

  • A
    $1$
  • B
    $\frac{41}{841}$
  • C
    $\frac{40}{441}$
  • D
    $\frac{41}{800}$

Explore More

Similar Questions

If $\theta$ lies in the first quadrant and $5 \tan \theta = 4$,then $\frac{5 \sin \theta - 3 \cos \theta}{\sin \theta + 2 \cos \theta}$ is equal to

Simplify the expression: $\frac{\cos x}{1+\sin x} + \tan x$

Which of the following trigonometric values are negative?
$I. \sin(-292^{\circ})$
$II. \tan(-190^{\circ})$
$III. \cos(-207^{\circ})$
$IV. \cot(-222^{\circ})$

If $\sin x = -\frac{3}{5}$,where $\pi < x < \frac{3\pi}{2}$,then $80(\tan^2 x - \cos x)$ is equal to:

The value of $\frac{\cot 54^{\circ}}{\tan 36^{\circ}} + \frac{\tan 20^{\circ}}{\cot 70^{\circ}}$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo