Let $m$ and $r$ be the dipole moment and radius of the Earth, respectively. Then, the Earth's magnetic field at the equator is

  • A
    $\frac{\mu_0}{4 \pi} \frac{m}{r^3}$
  • B
    $\frac{\mu_0}{8 \pi} \frac{m}{r^3}$
  • C
    $\frac{\mu_0}{2 \pi} \frac{m}{r^3}$
  • D
    $\frac{\mu_0}{\pi} \frac{m}{r^3}$

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Similar Questions

The ratio between the total intensity of the magnetic field at the equator to the poles is:

$A$ long straight horizontal cable carries a current of $2.5\;A$ in the direction $10^{\circ}$ south of west to $10^{\circ}$ north of east. The magnetic meridian of the place happens to be $10^{\circ}$ west of the geographic meridian. The earth's magnetic field at the location is $0.33\;G,$ and the angle of dip is zero. Locate the line of neutral points (ignore the thickness of the cable)? (At neutral points,magnetic field due to a current-carrying cable is equal and opposite to the horizontal component of earth's magnetic field.)

At a certain place,the angle of dip is $30^{\circ}$ and the horizontal component of the Earth's magnetic field is $0.5 \ G$. The Earth's total magnetic field (in $G$) at that place is:

The intensity of the magnetic field due to the Earth at a point inside a hollow steel box is:

Explain the angle of dip.

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