Let $A$ and $B$ be two events with $P(A^{C}) = 0.3$, $P(B) = 0.4$, and $P(A \cap B^{C}) = 0.5$. Then $P(B \mid A \cup B^{C})$ is equal to

  • A
    $\frac{1}{4}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{2}{3}$

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