Let V and H be the vertical and horizontal co | vedclass

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Question

(A) The Earth's magnetic field $B_E$ can be resolved into two components: the horizontal component $H = B_E \cos \delta$ and the vertical component $V

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$V >> H$

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(A) The Earth's magnetic field $B_E$ can be resolved into two components: the horizontal component $H = B_E \cos \delta$ and the vertical component $V = B_E \sin \delta$,where $\delta$ is the angle of dip.Near the North Pole,the magnetic field lines are almost perpendicular to the Earth's surface.Therefore,the angle of dip $\delta$ is nearly $90^{\circ}$.Since $\cos 90^{\circ} = 0$,the horizontal component $H$ becomes very small $(H \approx 0)$.Since $\sin 90^{\circ} = 1$,the vertical component $V$ becomes nearly equal to the total magnetic field $B_E$ $(V \approx B_E)$.Thus,near the North Pole,$V >> H$.

Let $V$ and $H$ be the vertical and horizontal components of the Earth's magnetic field at any point on Earth. Near the North Pole:

Similar Questions

The correct relation is:
$B_H$ = Horizontal component of earth's magnetic field; $B_V$ = Vertical component of earth's magnetic field and $B$ = Total intensity of earth's magnetic field.

At a certain place,the vertical component of the Earth's magnetic field is $\sqrt{3}$ times the horizontal component of the Earth's magnetic field. If a magnetic needle is suspended freely in the air,then it will incline:

The horizontal component of the Earth's magnetic field is $0.22 \ G$ and the total magnetic field is $0.4 \ G$. The angle of dip is:

What is the most accepted scientific explanation for the origin of the Earth's magnetic field?

The angle of dip at a place on the earth gives:

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