Let $A = \begin{bmatrix} 1 & 2 & 2 \\ 2 & 1 & 2 \\ 2 & 2 & 1 \end{bmatrix}$,then:

  • A
    $A^2 - 4A - 5I_3 = 0$
  • B
    $A^{-1} = \frac{1}{5} (A - 4I_3)$
  • C
    $A^2$ is invertible
  • D
    All of the above

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