Let $C$ be the curve $y = x^3$ (where $x$ takes all real values). The tangent at $A(t, t^3)$ meets the curve again at $B(T, T^3)$. If the gradient at $B$ is $K$ times the gradient at $A$,then $K$ is equal to

  • A
    $4$
  • B
    $2$
  • C
    $- 2$
  • D
    $\frac{1}{4}$

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