Let $I$ be the moment of inertia of a uniform square plate about an axis $AB$ that passes through its centre and is parallel to two of its sides. $CD$ is a line in the plane of the plate that passes through the centre of the plate and makes an angle $\theta$ with $AB$. The moment of inertia of the plate about the axis $CD$ is then equal to
- A$I$
- B$I \cos^2 \theta$
- C$I \sin^2 \theta$
- D$I \cos^2(\theta/2)$
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