Let the plane $P$ pass through the intersection of the planes $2x + 3y - z = 2$ and $x + 2y + 3z = 6$,and be perpendicular to the plane $2x + y - z + 1 = 0$. If $d$ is the distance of $P$ from the point $(-7, 1, 1)$,then $d^2$ is equal to:

  • A
    $\frac{250}{83}$
  • B
    $\frac{15}{53}$
  • C
    $\frac{25}{83}$
  • D
    $\frac{250}{82}$

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