Let the relation R be defined on the set of n | vedclass

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(A) The relation is defined as $3 a + 2 b = 27$,where $a, b \in N$ (natural numbers). Since $b = \frac{27 - 3 a}{2}$,for $b$ to be a natural number,$(

Vedclass · Accepted Answer

$\{(1, 12), (3, 9), (5, 6), (7, 3)\}$

Vedclass · Answer

(A) The relation is defined as $3 a + 2 b = 27$,where $a, b \in N$ (natural numbers). Since $b = \frac{27 - 3 a}{2}$,for $b$ to be a natural number,$(27 - 3 a)$ must be even and positive. If $a = 1$,$b = \frac{27 - 3}{2} = 12$. If $a = 3$,$b = \frac{27 - 9}{2} = 9$. If $a = 5$,$b = \frac{27 - 15}{2} = 6$. If $a = 7$,$b = \frac{27 - 21}{2} = 3$. If $a = 9$,$b = \frac{27 - 27}{2} = 0$,which is not in $N$. Thus,the relation $R = \{(1, 12), (3, 9), (5, 6), (7, 3)\}$. Therefore,option $A$ is correct.

List-$I$	List-$II$
$(A)$ Electron deficient hydride	$(I)$ $CH_4$
$(B)$ Electron precise hydride	$(II)$ $B_2H_6$
$(C)$ Electron rich hydride	$(III)$ $CaH_2$
$(D)$ Saline hydride	$(IV)$ $NiH_{0.6}$
	$(V)$ $PH_3$

Let the relation $R$ be defined on the set of natural numbers $N$ by $a R b$ if $3 a + 2 b = 27$. Then $R$ is:

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