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(C) Given the ratio of amplitudes of two light waves is $\frac{a_1}{a_2} = \frac{3}{2}$.Let $a_1 = 3k$ and $a_2 = 2k$,where $k$ is a constant.The inte

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$25: 1$

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(C) Given the ratio of amplitudes of two light waves is $\frac{a_1}{a_2} = \frac{3}{2}$.Let $a_1 = 3k$ and $a_2 = 2k$,where $k$ is a constant.The intensity $I$ is proportional to the square of the amplitude,$I \propto a^2$.The ratio of maximum intensity to minimum intensity in an interference pattern is given by the formula:$\frac{I_{\max}}{I_{\min}} = \frac{(a_1 + a_2)^2}{(a_1 - a_2)^2}$.Substituting the values:$\frac{I_{\max}}{I_{\min}} = \frac{(3k + 2k)^2}{(3k - 2k)^2} = \frac{(5k)^2}{(k)^2} = \frac{25k^2}{k^2} = \frac{25}{1}$.Thus,the intensity ratio is $25: 1$.

$x$	$0$	$1$	$2$	$3$	$4$	$5$
$f(x)$	$2$	$3$	$6$	$11$	$18$	$27$

Light waves producing interference have their amplitudes in the ratio $3: 2$. The intensity ratio of maximum and minimum of interference fringes is

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