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(N/A) Acceleration due to gravity $(g)$Universal gravitational constant $(G)$$(i)$ It is the acceleration acquired by a body due to the earth's gravit

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(N/A) Acceleration due to gravity $(g)$Universal gravitational constant $(G)$$(i)$ It is the acceleration acquired by a body due to the earth's gravitational pull on it.$(i)$ It is numerically equal to the force of attraction between two masses of $1\, kg$ each separated by a distance of $1\, m$.$(ii)$ The value of $g$ is different at different places on the surface of the earth and varies from one celestial body to another.$(ii)$ The value of $G$ is a universal constant,i.e.,its value is the same $(6.67 	imes 10^{-11}\, Nm^2 kg^{-2})$ everywhere in the universe.$(iii)$ It is a vector quantity.$(iii)$ It is a scalar quantity.

List in tabular form any three differences between $g$ and $G$.

Similar Questions

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Why is the value of $g$ greater at the poles than at the equator?

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Acceleration due to gravity $(g)$	Universal gravitational constant $(G)$
$(i)$ It is the acceleration acquired by a body due to the earth's gravitational pull on it.	$(i)$ It is numerically equal to the force of attraction between two masses of $1\, kg$ each separated by a distance of $1\, m$.
$(ii)$ The value of $g$ is different at different places on the surface of the earth and varies from one celestial body to another.	$(ii)$ The value of $G$ is a universal constant,i.e.,its value is the same $(6.67 \times 10^{-11}\, Nm^2 kg^{-2})$ everywhere in the universe.
$(iii)$ It is a vector quantity.	$(iii)$ It is a scalar quantity.