Look at the graphs $(a)$ to $(d)$ carefully and state,with reasons,which of these cannot possibly represent one-dimensional motion of a particle.
(ALL OF THE ABOVE) The given $x-t$ graph,shown in $(a)$,does not represent one-dimensional motion of the particle. This is because a particle cannot have two positions at the same instant of time.
The given $v-t$ graph,shown in $(b)$,does not represent one-dimensional motion of the particle. This is because a particle can never have two values of velocity at the same instant of time.
The given speed-time graph,shown in $(c)$,does not represent one-dimensional motion of the particle. This is because speed is a scalar quantity and cannot be negative.
The given total path length-time graph,shown in $(d)$,does not represent one-dimensional motion of the particle. This is because the total path length (distance) travelled by a particle can never decrease with time.
The given $v-t$ graph,shown in $(b)$,does not represent one-dimensional motion of the particle. This is because a particle can never have two values of velocity at the same instant of time.
The given speed-time graph,shown in $(c)$,does not represent one-dimensional motion of the particle. This is because speed is a scalar quantity and cannot be negative.
The given total path length-time graph,shown in $(d)$,does not represent one-dimensional motion of the particle. This is because the total path length (distance) travelled by a particle can never decrease with time.
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Read each statement below carefully and state with reasons and examples,if it is true or false for a particle in one-dimensional motion:
$(a)$ With zero speed at an instant may have non-zero acceleration at that instant.
$(b)$ With zero speed may have non-zero velocity.
$(c)$ With constant speed must have zero acceleration.
$(d)$ With positive value of acceleration must be speeding up.
$(a)$ With zero speed at an instant may have non-zero acceleration at that instant.
$(b)$ With zero speed may have non-zero velocity.
$(c)$ With constant speed must have zero acceleration.
$(d)$ With positive value of acceleration must be speeding up.
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