(C) In the compound $A_2 B$,the atom $B$ exists as $B^{-2}$ ion.For an atom to achieve the lowest oxidation state of $-2$,it must gain $2$ electrons t

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(C) In the compound $A_2 B$,the atom $B$ exists as $B^{-2}$ ion.For an atom to achieve the lowest oxidation state of $-2$,it must gain $2$ electrons to complete its octet.This implies that the atom $B$ has $6$ electrons in its valence shell in its neutral atomic state ($6 + 2 = 8$ electrons).Therefore,the number of valence electrons in atom $B$ is $6$.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Valency and oxidation state

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The lowest oxidation number of an atom $B$ in a compound $A_2 B$ is $-2$. The number of electrons in its valence shell is:

JEE MAIN 2024 All JEE MAIN

A
$4$
B
$5$
C
$6$
D
$7$

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Class 11 Questions

Class 11

Chemistry Questions

Chapter

Classification of Elements and Periodicity in Properties

Subtopic

Valency and oxidation state

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The lowest oxidation number of an atom $B$ in a compound $A_2 B$ is $-2$. The number of electrons in its valence shell is:

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Explain the periodicity of valence or oxidation states and explain the oxidation states of oxygen in $Na_2O$ and $OF_2$.

Describe the periodic trends in the valence of elements with respect to their oxides and hydrides.

The general formula of the compound formed when a metal $(M)$ of group $1$ reacts with a non-metal $(X)$ of group $16$ is:

Which of the oxidation state$(s)$ is/are shown by the element sulphur?

The valency (oxidation state) of phosphorus in $H_3PO_4$ is

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