m-chlorobenzaldehyde on treatment with 50 % K | vedclass

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(B) $m$-chlorobenzaldehyde does not have any $\alpha$-hydrogen atom. Therefore,it undergoes the Cannizzaro reaction in the presence of a concentrated

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(B) $m$-chlorobenzaldehyde does not have any $\alpha$-hydrogen atom. Therefore,it undergoes the Cannizzaro reaction in the presence of a concentrated base like $50 \% KOH$. In this reaction,one molecule of the aldehyde is oxidized to the corresponding carboxylate ion ($m$-chlorobenzoate) and another molecule is reduced to the corresponding alcohol ($m$-chlorobenzyl alcohol). The reaction is as follows:$2 	ext{ } m	ext{-Cl-C}_6	ext{H}_4	ext{CHO} + KOH$ $ightarrow m	ext{-Cl-C}_6	ext{H}_4	ext{COO}^- 	ext{K}^+ + m	ext{-Cl-C}_6	ext{H}_4	ext{CH}_2	ext{OH}$

$m$-chlorobenzaldehyde on treatment with $50 \% KOH$ solution yields

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