Magnetic lines of force due to a bar magnet do not intersect because

What happens to the force between two magnetic poles when their pole strength and the distance between them are both doubled?

Each atom of an iron bar $(5 \, cm \times 1 \, cm \times 1 \, cm)$ has a magnetic moment of $1.8 \times 10^{-23} \, A \cdot m^2$. Given that the density of iron is $7.78 \times 10^3 \, kg/m^3$,the atomic weight is $56 \, g/mol$,and Avogadro's number is $6.02 \times 10^{23} \, mol^{-1}$,calculate the magnetic moment of the bar in the state of magnetic saturation in $A \cdot m^2$.

The distance between the poles of a horse shoe magnet is $0.1\, m$ and its pole strength is $0.01\, A\cdot m$. The induction of magnetic field at a point midway between the poles will be

Two identical thin bar magnets are placed mutually at right angles such that the north pole of one touches the south pole of the other. The length of each bar magnet is $\ell$. The magnitude of the resultant magnetic moment of the system is $[m = \text{pole strength of the magnet}]$.

The magnetic field lines of a bar magnet