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(D) $1$. The reaction of benzene with Fenton's reagent $(Fe^{+2} / H_2O_2)$ produces phenol as product $(A)$.$2$. Phenol reacts with bromine water $(B

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$2,4,6-$Tribromophenol

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(D) $1$. The reaction of benzene with Fenton's reagent $(Fe^{+2} / H_2O_2)$ produces phenol as product $(A)$.$2$. Phenol reacts with bromine water $(Br_2 / H_2O)$ to undergo electrophilic aromatic substitution.$3$. Due to the strong activating effect of the $-OH$ group,the reaction proceeds to substitute all available ortho and para positions,resulting in the formation of $2,4,6-$tribromophenol as the major product $(B)$.

The major product $(B)$ of this reaction is:

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