The major product B of the following reaction | vedclass

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(A) Step $1$: Ethylbenzene reacts with alkaline $KMnO_4$ followed by heating to undergo oxidation of the alkyl side chain to form potassium benzoate $

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$5$

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(A) Step $1$: Ethylbenzene reacts with alkaline $KMnO_4$ followed by heating to undergo oxidation of the alkyl side chain to form potassium benzoate $(A)$.Step $2$: Potassium benzoate $(A)$ upon treatment with nitrating mixture $(conc. HNO_3 + conc. H_2SO_4)$ undergoes electrophilic aromatic substitution. Since the $-COOH$ group is meta-directing,the nitro group enters the meta position to form $m$-nitrobenzoic acid $(B)$.Step $3$: The structure of $B$ ($m$-nitrobenzoic acid) contains:- $3$ $\pi$-bonds in the benzene ring.- $1$ $\pi$-bond in the $C=O$ group of the carboxylic acid.- $1$ $\pi$-bond in the $N=O$ group of the nitro group.Total $\pi$-bonds = $3 + 1 + 1 = 5$.

The major product $B$ of the following reaction has . . . . . . . $\pi$-bonds.

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