The major product for the above reaction is:

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(A) The reaction is an aromatic nucleophilic substitution $(S_N^{Ar})$ reaction. In the given substrate,the $-NO_2$ group is a strong electron-withdra

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$1-$bromo$-3-$fluoro$-5-$(methylthio)$-4-$nitrobenzene

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(A) The reaction is an aromatic nucleophilic substitution $(S_N^{Ar})$ reaction. In the given substrate,the $-NO_2$ group is a strong electron-withdrawing group at the para position relative to the fluorine atoms. Nucleophilic substitution occurs at the position ortho or para to the electron-withdrawing group. Here,the fluorine atom at the para position relative to the $-NO_2$ group is the most activated for nucleophilic attack by the nucleophile $CH_3S^-$. Therefore,the $CH_3S$ group replaces the para-fluorine atom to form the major product.

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Two benzyne intermediates are likely to be formed equally. Reaction with amide ion can occur in two different directions with each benzyne,giving three possible products. They are formed in a $1 : 2 : 1$ ratio. Asterisk $(*)$ refers to $^{14}C$. Product $(A)$ is:

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