The major product formed in the following rea | vedclass

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(D) The reaction of an ether with $HI$ proceeds via the protonation of the ether oxygen atom,followed by the cleavage of the $C-O$ bond. In the given

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Cyclohexanol and $2-$iodo$-2-$methylpropane

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(D) The reaction of an ether with $HI$ proceeds via the protonation of the ether oxygen atom,followed by the cleavage of the $C-O$ bond. In the given ether,cyclohexyl tert-butyl ether,the cleavage occurs such that the more stable carbocation is formed. The tert-butyl group forms a stable tertiary carbocation $(CH_3)_3C^+$,which is then attacked by the iodide ion $(I^-)$ to form tert-butyl iodide,$(CH_3)_3CI$. The cyclohexyl group remains as the alcohol,cyclohexanol $(C_6H_{11}OH)$. Thus,the major products are cyclohexanol and $2-$iodo$-2-$methylpropane (tert-butyl iodide).

The major product formed in the following reaction is a mixture of:

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The major product in the given reaction will be:
(One mole of each)
$C_6H_5O^-Na^+ + C_6H_5CH_2Cl + C_2H_5OK^+ \xrightarrow{\text{Major Product}}$

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The major products $C$ and $D$ formed in the following reaction are:
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