The major product of the given reaction is:

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(A) The reaction involves the acid-catalyzed dimerization of isobutylene ($2$-methylpropene) with ethene. $1$. Protonation of isobutylene forms a stab

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$2,3-$Dimethylbut$-2-$ene

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(A) The reaction involves the acid-catalyzed dimerization of isobutylene ($2$-methylpropene) with ethene. $1$. Protonation of isobutylene forms a stable $3^{\circ}$ carbocation: $(CH_3)_2C^+-CH_3$. $2$. This carbocation attacks ethene to form a new carbocation: $(CH_3)_3C-CH_2-CH_2^+$. $3$. Through a series of rearrangements ($1,2$-hydride shift followed by $1,2$-methyl shift),the carbocation rearranges to a more stable form. $4$. Finally,deprotonation leads to the most stable alkene,which is $2,3$-dimethylbut-$2$-ene.

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