Manganese achieves its highest oxidation stat | vedclass

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(C) To find the oxidation state of $Mn$ in each compound:$1$. In $MnO_3$: $x + 3(-2) = 0 \implies x = +6$.$2$. In $Mn_3O_4$: $3x + 4(-2) = 0 \implies

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$KMnO_4$

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(C) To find the oxidation state of $Mn$ in each compound:$1$. In $MnO_3$: $x + 3(-2) = 0 \implies x = +6$.$2$. In $Mn_3O_4$: $3x + 4(-2) = 0 \implies 3x = 8 \implies x = +8/3 \approx +2.67$.$3$. In $KMnO_4$: $1 + x + 4(-2) = 0 \implies x - 7 = 0 \implies x = +7$.$4$. In $K_2MnO_4$: $2(1) + x + 4(-2) = 0 \implies x - 6 = 0 \implies x = +6$.The highest oxidation state of $Mn$ is $+7$,which is achieved in $KMnO_4$.

Manganese achieves its highest oxidation state in which of the following compounds?

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