Manmohan spends frac{1}{5} part of his money | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the total monthly income of Manmohan be $x$.Step $1$: Pocket money spent is $\frac{1}{5}x$.Step $2$: The remainder after pocket money is $x -

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(D) Let the total monthly income of Manmohan be $x$.Step $1$: Pocket money spent is $\frac{1}{5}x$.Step $2$: The remainder after pocket money is $x - \frac{1}{5}x = \frac{4}{5}x$.Step $3$: He spends $\frac{4}{5}$ of the remainder on other affairs,so other expenses = $\frac{4}{5} 	imes \frac{4}{5}x = \frac{16}{25}x$.Step $4$: The final saving is the remainder minus other expenses: $\frac{4}{5}x - \frac{16}{25}x = \frac{20x - 16x}{25} = \frac{4}{25}x$.Step $5$: Given that the saving is $Rs.\, 48$,we have $\frac{4}{25}x = 48$.Step $6$: Solving for $x$: $x = 48 	imes \frac{25}{4} = 12 	imes 25 = 300$.Therefore,his monthly income is $Rs.\, 300$.

Manmohan spends $\frac{1}{5}$ part of his money as pocket money and $\frac{4}{5}$ of the remainder in other affairs. If he is left with $Rs.\, 48$ per month,what is his monthly income? (in $Rs.$)

Similar Questions

$7 \frac{1}{2}-\left[2 \frac{1}{4} \div\left\{1 \frac{1}{4}-x\left(1 \frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\right\}\right]=3$. Find the value of $x$.

$\frac{(469+174)^{2}-(469-174)^{2}}{469 \times 174} = ?$

If $x^{3}+3x^{2}+3x=7,$ then $x$ is equal to

The value of: $\sqrt{\frac{0.324 \times 0.081 \times 4.624}{1.5625 \times 0.0289 \times 72.9 \times 64}}$

If $a = \sqrt{2} + 1$ and $b = \sqrt{2} - 1,$ then the value of $\frac{1}{a + 1} + \frac{1}{b + 1}$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module