Markownikoff's rule provides guidance for the | vedclass

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Question

(D) Markownikoff's rule is applicable to the addition of unsymmetrical reagents to unsymmetrical alkenes. In the case of $CH_2 = CHBr$ (vinyl bromide)

Vedclass · Accepted Answer

$CH_2 = CHBr$

Vedclass · Answer

(D) Markownikoff's rule is applicable to the addition of unsymmetrical reagents to unsymmetrical alkenes. In the case of $CH_2 = CHBr$ (vinyl bromide),the alkene is unsymmetrical. According to Markownikoff's rule,the positive part of the reagent $(H^+)$ attaches to the carbon atom of the double bond that has a greater number of hydrogen atoms,while the negative part $(Br^-)$ attaches to the carbon atom with fewer hydrogen atoms. Thus,the reaction proceeds as: $CH_2 = CHBr + HBr \rightarrow CH_3 - CH(Br)_2$.

Markownikoff's rule provides guidance for the addition of $HBr$ on:

Similar Questions

The reaction of bromine with an alkene is an example of which of the following?

Ethylene reacts with bromine to form

Product $(A)$ is:
(cyclobutylidene)methylcyclopropane + $HBr \rightarrow A$ (Major)

For the reaction: $CH_2=CH-CH=CH_2 + HBr (1 \text{ eq}) \xrightarrow{80^{\circ}C} P_1 + P_2$ (where $P_1$ is the major product),identify $P_1$.

Ozonolysis of the given compound yields:

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