Match each coordination compound in List-$I$ with an appropriate pair of characteristics from List-$II$ and select the correct answer using the code given below the lists.
$\{ en = H_2NCH_2CH_2NH_2 \}$; atomic numbers: $\{Ti = 22; Cr = 24; Co = 27; Pt = 78\}$
List-$I$ List-$II$ $P.$ $[Cr(NH_3)_4Cl_2]Cl$ $1.$ Paramagnetic and exhibits ionisation isomerism $Q.$ $[Ti(H_2O)_5Cl](NO_3)_2$ $2.$ Diamagnetic and exhibits cis-trans isomerism $R.$ $[Pt(en)(NH_3)_2Cl_2]NO_3$ $3.$ Paramagnetic and exhibits cis-trans isomerism $S.$ $[Co(NH_3)_4(NO_3)_2]NO_3$ $4.$ Diamagnetic and exhibits ionisation isomerism Codes: $P, Q, R, S$
$\{ en = H_2NCH_2CH_2NH_2 \}$; atomic numbers: $\{Ti = 22; Cr = 24; Co = 27; Pt = 78\}$
| List-$I$ | List-$II$ |
| $P.$ $[Cr(NH_3)_4Cl_2]Cl$ | $1.$ Paramagnetic and exhibits ionisation isomerism |
| $Q.$ $[Ti(H_2O)_5Cl](NO_3)_2$ | $2.$ Diamagnetic and exhibits cis-trans isomerism |
| $R.$ $[Pt(en)(NH_3)_2Cl_2]NO_3$ | $3.$ Paramagnetic and exhibits cis-trans isomerism |
| $S.$ $[Co(NH_3)_4(NO_3)_2]NO_3$ | $4.$ Diamagnetic and exhibits ionisation isomerism |
| Codes: $P, Q, R, S$ |
- A$3, 1, 4, 2$
- B$3, 1, 2, 4$
- C$2, 1, 3, 4$
- D$1, 3, 4, 2$
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View SolutionThe ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by $NiCl_2 \cdot 6H_2O$ to form a stable coordination compound. Assume that both the reactions are $100 \%$ complete. If $1584 \ g$ of ammonium sulphate and $952 \ g$ of $NiCl_2 \cdot 6H_2O$ are used in the preparation,the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is $\qquad$ (Atomic weights in $g \ mol^{-1}: H=1, N=14, O=16, S=32, Cl=35.5, Ca=40, Ni=59$)
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$(ii)$ $[Co(NH_3)_5Cl]Cl_2$
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$(i)$ $K[Cr(H_2O)_2(C_2O_4)_2] \cdot 3H_2O$
$(ii)$ $[Co(NH_3)_5Cl]Cl_2$
$(iii)$ $CrCl_3(py)_3$
$(iv)$ $Cs[FeCl_4]$
$(v)$ $K_4[Mn(CN)_6]$
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$1\,L$ Solution $(X) + AgNO_3$ solution (excess) $\rightarrow Y$
$1\,L$ Solution $(X) + BaCl_2$ solution (excess) $\rightarrow Z$
The number of moles of $Y$ and $Z$ respectively are:
$1\,L$ Solution $(X) + AgNO_3$ solution (excess) $\rightarrow Y$
$1\,L$ Solution $(X) + BaCl_2$ solution (excess) $\rightarrow Z$
The number of moles of $Y$ and $Z$ respectively are:
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