Match List-I with List-II. List-I (React | vedclass

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(C) The reactions are as follows:$A$. Phenol reacts with $Zn$ dust upon heating to form Benzene $(III)$.$B$. Phenol reacts with $CHCl_3$ and $NaOH$ fo

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$A-III, B-I, C-II, D-IV$

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(C) The reactions are as follows:$A$. Phenol reacts with $Zn$ dust upon heating to form Benzene $(III)$.$B$. Phenol reacts with $CHCl_3$ and $NaOH$ followed by acidification $(HCl)$ to form Salicylaldehyde $(I)$ (Reimer-Tiemann reaction).$C$. Phenol reacts with $CO_2$ and $NaOH$ followed by acidification $(HCl)$ to form Salicylic acid $(II)$ (Kolbe-Schmidt reaction).$D$. Phenol reacts with concentrated $HNO_3$ to form $2,4,6$-trinitrophenol,commonly known as Picric acid $(IV)$.Therefore,the correct matching is $A-III, B-I, C-II, D-IV$.

List-$I$ (Reactants)	List-$II$ (Products)
$A$. Phenol,$Zn / \Delta$	$I$. Salicylaldehyde
$B$. Phenol,$CHCl_3, NaOH, HCl$	$II$. Salicylic acid
$C$. Phenol,$CO_2, NaOH, HCl$	$III$. Benzene
$D$. Phenol,Conc. $HNO_3$	$IV$. Picric acid

Match List-$I$ with List-$II$.

List-$I$ (Reactants) List-$II$ (Products)

$A$. Phenol,$Zn / \Delta$ $I$. Salicylaldehyde

$B$. Phenol,$CHCl_3, NaOH, HCl$ $II$. Salicylic acid

$C$. Phenol,$CO_2, NaOH, HCl$ $III$. Benzene

$D$. Phenol,Conc. $HNO_3$ $IV$. Picric acid

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Match List-$I$ with List-$II$. List-$I$ (Reactants) List-$II$ (Products) $A$. Phenol,$Zn / \Delta$ $I$. Salicylaldehyde $B$. Phenol,$CHCl_3, NaOH, HCl$ $II$. Salicylic acid $C$. Phenol,$CO_2, NaOH, HCl$ $III$. Benzene $D$. Phenol,Conc. $HNO_3$ $IV$. Picric acid