Match List-I with List-II and select the corr | vedclass

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(A) $1$. $XeF_4$: It has $4$ bond pairs and $2$ lone pairs,resulting in square planar geometry with bond angles of $90^o$. Thus,$I-C$.$2$. $I_3^-$: It

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$I-C, II-D, III-A, IV-B$

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(A) $1$. $XeF_4$: It has $4$ bond pairs and $2$ lone pairs,resulting in square planar geometry with bond angles of $90^o$. Thus,$I-C$.$2$. $I_3^-$: It has $2$ bond pairs and $3$ lone pairs on the central atom,resulting in a linear geometry. Thus,$II-D$.$3$. $XeO_2F_2$: It has $4$ bond pairs and $1$ lone pair,resulting in a see-saw shape. Thus,$III-A$.$4$. $SO_4^{2-}$: It has $4$ bond pairs and $0$ lone pairs,resulting in a tetrahedral geometry. Thus,$IV-B$.Therefore,the correct matching is $I-C, II-D, III-A, IV-B$.

List-$I$	List-$II$
$I$. $XeF_4$	$A$. See-saw
$II$. $I_3^-$	$B$. Tetrahedral
$III$. $XeO_2F_2$	$C$. Bond angle $90^o$
$IV$. $SO_4^{2-}$	$D$. Linear

Match List-$I$ with List-$II$ and select the correct answer using the codes given below the lists.

List-$I$ List-$II$

$I$. $XeF_4$ $A$. See-saw

$II$. $I_3^-$ $B$. Tetrahedral

$III$. $XeO_2F_2$ $C$. Bond angle $90^o$

$IV$. $SO_4^{2-}$ $D$. Linear

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Match List-$I$ with List-$II$ and select the correct answer using the codes given below the lists. List-$I$ List-$II$ $I$. $XeF_4$ $A$. See-saw $II$. $I_3^-$ $B$. Tetrahedral $III$. $XeO_2F_2$ $C$. Bond angle $90^o$ $IV$. $SO_4^{2-}$ $D$. Linear