Match List-I with List-II and select the corr | vedclass

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(A) $(i) \, Ni^{2+}$ reacts with Dimethylglyoxime $(DMG)$ to form a rosy red precipitate of $[Ni(DMG)_2]$. Thus,$(i) - D$.$(ii) \, Ag^{+}$ reacts with

Vedclass · Accepted Answer

$D-A-C-B$

Vedclass · Answer

(A) $(i) \, Ni^{2+}$ reacts with Dimethylglyoxime $(DMG)$ to form a rosy red precipitate of $[Ni(DMG)_2]$. Thus,$(i) - D$.$(ii) \, Ag^{+}$ reacts with Sodium thiosulphate $(Na_2S_2O_3)$ to form a soluble complex $Na_3[Ag(S_2O_3)_2]$. Thus,$(ii) - A$.$(iii) \, Cu^{2+}$ reacts with Ammonia $(NH_3)$ to form a deep blue complex $[Cu(NH_3)_4]^{2+}$. Thus,$(iii) - C$.$(iv) \, S^{2-}$ reacts with Sodium nitroprusside $(Na_2[Fe(CN)_5NO])$ to form a purple colored complex $Na_4[Fe(CN)_5(NOS)]$. Thus,$(iv) - B$.Therefore,the correct matching is $(i)-D, (ii)-A, (iii)-C, (iv)-B$.

List-$I$ (Ion involved)	List-$II$ (Agent)
$(i) \, Ni^{2+}$	$(A).$ Sodium thiosulphate
$(ii) \, Ag^{+}$	$(B).$ Sodium nitroprusside
$(iii) \, Cu^{2+}$	$(C).$ Ammonia
$(iv) \, S^{2-}$	$(D).$ Dimethylglyoxime

Match List-$I$ with List-$II$ and select the correct answer using the codes given below.

List-$I$ (Ion involved) List-$II$ (Agent)

$(i) \, Ni^{2+}$ $(A).$ Sodium thiosulphate

$(ii) \, Ag^{+}$ $(B).$ Sodium nitroprusside

$(iii) \, Cu^{2+}$ $(C).$ Ammonia

$(iv) \, S^{2-}$ $(D).$ Dimethylglyoxime

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Match List-$I$ with List-$II$ and select the correct answer using the codes given below. List-$I$ (Ion involved) List-$II$ (Agent) $(i) \, Ni^{2+}$ $(A).$ Sodium thiosulphate $(ii) \, Ag^{+}$ $(B).$ Sodium nitroprusside $(iii) \, Cu^{2+}$ $(C).$ Ammonia $(iv) \, S^{2-}$ $(D).$ Dimethylglyoxime