Match List I with List II and select the corr | vedclass

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(C) To determine the oxidation state of $N$ in each compound:$(A)$ In $NO_2$: $x + 2(-2) = 0 \Rightarrow x = +4$. Thus,$(A) \rightarrow (3)$.$(B)$ In

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$3, 4, 2, 1$

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(C) To determine the oxidation state of $N$ in each compound:$(A)$ In $NO_2$: $x + 2(-2) = 0 \Rightarrow x = +4$. Thus,$(A) \rightarrow (3)$.$(B)$ In $HNO$: $+1 + x + (-2) = 0 \Rightarrow x = +1$. Thus,$(B) \rightarrow (4)$.$(C)$ In $NH_3$: $x + 3(+1) = 0 \Rightarrow x = -3$. Thus,$(C) \rightarrow (2)$.$(D)$ In $N_2O_5$: $2x + 5(-2) = 0$ $\Rightarrow 2x = 10$ $\Rightarrow x = +5$. Thus,$(D) \rightarrow (1)$.The correct sequence is $3, 4, 2, 1$.

List $I$ (Compound)	List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$	$(1)$ $+5$
$(B)$ $HNO$	$(2)$ $-3$
$(C)$ $NH_3$	$(3)$ $+4$
$(D)$ $N_2O_5$	$(4)$ $+1$

Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:
List $I$ (Compound) List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$ $(1)$ $+5$
$(B)$ $HNO$ $(2)$ $-3$
$(C)$ $NH_3$ $(3)$ $+4$
$(D)$ $N_2O_5$ $(4)$ $+1$

Codes: $A \quad B \quad C \quad D$

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Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:List $I$ (Compound)List $II$ (Oxidation state of $N$)$(A)$ $NO_2$$(1)$ $+5$$(B)$ $HNO$$(2)$ $-3$$(C)$ $NH_3$$(3)$ $+4$$(D)$ $N_2O_5$$(4)$ $+1$Codes: $A \quad B \quad C \quad D$