Match List $-I$ with List $-II.$

List $-I$ (Products formed)	List $-II$ (Reaction of carbonyl compound with)
$(a).$ Cyanohydrin	$(i).$ $NH_2OH$
$(b).$ Acetal	$(ii).$ $RNH_2$
$(c).$ Schiff's base	$(iii).$ Alcohol
$(d).$ Oxime	$(iv).$ $HCN$

Choose the correct answer from the options given below:

$A$ mixture of benzaldehyde and formaldehyde on heating with aqueous $NaOH$ solution gives :-

Compounds $P$ and $R$ upon ozonolysis produce $Q$ and $S$,respectively. The molecular formula of $Q$ and $S$ is $C_8H_8O$. $Q$ undergoes Cannizzaro reaction but not haloform reaction,whereas $S$ undergoes haloform reaction but not Cannizzaro reaction.
$(i)$ $P \xrightarrow[\text{ii) } Zn / H_2O]{\text{i) } O_3 / CH_2Cl_2} \underset{(C_8H_8O)}{Q}$
$(ii)$ $R \xrightarrow[\text{ii) } Zn / H_2O]{\text{i) } O_3 / CH_2Cl_2} \underset{(C_8H_8O)}{S}$
The option$(s)$ with a suitable combination of $P$ and $R$,respectively,is(are):

Which of the following reagents can be used for the given chemical transformation?

The Clemmensen reduction is represented by:

Compound $P$ $(C_{8}H_{8}O)$ gives a red-orange precipitate with $2,4-DNP$ reagent and it does not reduce Fehling's reagent. On drastic oxidation with chromic acid, $P$ gives an aromatic product $Q$ that produces effervescence on treating with aqueous $NaHCO_{3}$. Compound $P$ and $Q$, respectively, are: