Match List-$I$ with List-$II$.
List-$I$ List-$II$
$(A)$ Torque $(I)$ $Nms^{-1}$
$(B)$ Stress $(II)$ $Jkg^{-1}$
$(C)$ Latent Heat $(III)$ $Nm$
$(D)$ Power $(IV)$ $Nm^{-2}$

Choose the correct answer from the options below.

  • A
    $(A)-(III), (B)-(II), (C)-(I), (D)-(IV)$
  • B
    $(A)-(III), (B)-(IV), (C)-(II), (D)-(I)$
  • C
    $(A)-(IV), (B)-(I), (C)-(III), (D)-(II)$
  • D
    $(A)-(II), (B)-(III), (C)-(I), (D)-(IV)$

Explore More

Similar Questions

State whether the following statements are true or false:
$(a)$ $A$ physical quantity can have units but still be dimensionless.
$(b)$ Impulse and the gradient of energy have the same units.
$(c)$ The absolute error in every measurement is equal to the least count of the measuring instrument.

The density of a substance is $4 \, g/cc$ in a system in which the unit of length is $5 \, cm$ and the unit of mass is $20 \, g$. The density of the substance in the $CGS$ system is: (in $units$)

Match List-$I$ with List-$II$.
List-$I$List-$II$
$(A)$ Mass density$(I)$ $[ML^2T^{-3}]$
$(B)$ Impulse$(II)$ $[MLT^{-1}]$
$(C)$ Power$(III)$ $[ML^2T^0]$
$(D)$ Moment of inertia$(IV)$ $[ML^{-3}T^0]$
Choose the correct answer from the options given below:

To determine Young's modulus of a wire,the formula is $Y = \frac{F}{A} \cdot \frac{L}{\Delta L}$,where $F/A$ is the stress and $L/\Delta L$ is the reciprocal of strain. The conversion factor to change $Y$ from $CGS$ to $MKS$ system is:

The unit $J \cdot s^2$ corresponds to which physical quantity?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo